17412351320939 has 2 divisors, whose sum is σ = 17412351320940. Its totient is φ = 17412351320938.

The previous prime is 17412351320869. The next prime is 17412351320941. The reversal of 17412351320939 is 93902315321471.

It is a strong prime.

It is an emirp because it is prime and its reverse (93902315321471) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-17412351320939 is a prime.

It is a super-3 number, since 3×17412351320939³ (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 17412351320941, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (17412351320839) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8706175660469 + 8706175660470.

It is an arithmetic number, because the mean of its divisors is an integer number (8706175660470).

Almost surely, 2^{17412351320939} is an apocalyptic number.

17412351320939 is a deficient number, since it is larger than the sum of its proper divisors (1).

17412351320939 is an equidigital number, since it uses as much as digits as its factorization.

17412351320939 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1224720, while the sum is 50.

The spelling of 17412351320939 in words is "seventeen trillion, four hundred twelve billion, three hundred fifty-one million, three hundred twenty thousand, nine hundred thirty-nine".