Base | Representation |
---|---|
bin | 11010010111110101101… |
… | …111001111100110011011 |
3 | 20102020212120202212100011 |
4 | 122113311233033212123 |
5 | 214143044313043303 |
6 | 3504321101022351 |
7 | 244635404055625 |
oct | 32276557174633 |
9 | 6366776685304 |
10 | 1812304034203 |
11 | 6396594206a3 |
12 | 2532a0b549b7 |
13 | 101b9038ab10 |
14 | 63a0492dc15 |
15 | 3221ed3316d |
hex | 1a5f5bcf99b |
1812304034203 has 16 divisors (see below), whose sum is σ = 2067422797440. Its totient is φ = 1573801491456.
The previous prime is 1812304034171. The next prime is 1812304034249. The reversal of 1812304034203 is 3024304032181.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 1812304034203 - 25 = 1812304034171 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1812304034003) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1287418 + ... + 2298271.
It is an arithmetic number, because the mean of its divisors is an integer number (129213924840).
Almost surely, 21812304034203 is an apocalyptic number.
1812304034203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1812304034203 is a deficient number, since it is larger than the sum of its proper divisors (255118763237).
1812304034203 is a wasteful number, since it uses less digits than its factorization.
1812304034203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3588006.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 1812304034203 its reverse (3024304032181), we get a palindrome (4836608066384).
The spelling of 1812304034203 in words is "one trillion, eight hundred twelve billion, three hundred four million, thirty-four thousand, two hundred three".
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