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1812321539952 = 2437111997266059
BaseRepresentation
bin11010010111110110110…
…010000001011101110000
320102020220210201020201020
4122113312302001131300
5214143113303234302
63504322524135440
7244636005626040
oct32276662013560
96366823636636
101812321539952
11639668297a60
122532a6997580
13101b93ba9b51
1463a06da9720
153222163eebc
hex1a5f6c81770

1812321539952 has 320 divisors, whose sum is σ = 6207669350400. Its totient is φ = 441358295040.

The previous prime is 1812321539927. The next prime is 1812321539989. The reversal of 1812321539952 is 2599351232181.

It is a junction number, because it is equal to n+sod(n) for n = 1812321539895 and 1812321539904.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 6678699 + ... + 6944757.

It is an arithmetic number, because the mean of its divisors is an integer number (19398966720).

Almost surely, 21812321539952 is an apocalyptic number.

1812321539952 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1812321539952, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3103834675200).

1812321539952 is an abundant number, since it is smaller than the sum of its proper divisors (4395347810448).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1812321539952 is a wasteful number, since it uses less digits than its factorization.

1812321539952 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 266204 (or 266198 counting only the distinct ones).

The product of its digits is 1166400, while the sum is 51.

The spelling of 1812321539952 in words is "one trillion, eight hundred twelve billion, three hundred twenty-one million, five hundred thirty-nine thousand, nine hundred fifty-two".