1861103483140 has 48 divisors (see below), whose sum is σ = 4289776142400. Its totient is φ = 672612958080.

The previous prime is 1861103483117. The next prime is 1861103483207. The reversal of 1861103483140 is 413843011681.

It is a junction number, because it is equal to n+sod(n) for n = 1861103483093 and 1861103483102.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25913715 + ... + 25985434.

It is an arithmetic number, because the mean of its divisors is an integer number (89370336300).

Almost surely, 2^{1861103483140} is an apocalyptic number.

1861103483140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1861103483140 is an abundant number, since it is smaller than the sum of its proper divisors (2428672659260).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1861103483140 is a wasteful number, since it uses less digits than its factorization.

1861103483140 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51899332 (or 51899330 counting only the distinct ones).

The product of its (nonzero) digits is 55296, while the sum is 40.

The spelling of 1861103483140 in words is "one trillion, eight hundred sixty-one billion, one hundred three million, four hundred eighty-three thousand, one hundred forty".