1861894271350 has 24 divisors (see below), whose sum is σ = 3463991884080. Its totient is φ = 744570925920.

The previous prime is 1861894271291. The next prime is 1861894271353. The reversal of 1861894271350 is 531724981681.

It is a junction number, because it is equal to n+sod(n) for n = 1861894271291 and 1861894271300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1861894271353) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 4468122 + ... + 4867021.

It is an arithmetic number, because the mean of its divisors is an integer number (144332995170).

It is a 1-persistent number, because it is pandigital, but 2⋅1861894271350 = 3723788542700 is not.

Almost surely, 2^{1861894271350} is an apocalyptic number.

1861894271350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1861894271350 is a deficient number, since it is larger than the sum of its proper divisors (1602097612730).

1861894271350 is a wasteful number, since it uses less digits than its factorization.

1861894271350 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9339144 (or 9339139 counting only the distinct ones).

The product of its (nonzero) digits is 2903040, while the sum is 55.

The spelling of 1861894271350 in words is "one trillion, eight hundred sixty-one billion, eight hundred ninety-four million, two hundred seventy-one thousand, three hundred fifty".