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19339325744413 is a prime number
BaseRepresentation
bin1000110010110110010011…
…01001000010010100011101
32112110211011212021220122011
410121123021221002110131
510013323414342310123
6105044210311551221
74034135343350263
oct431331151022435
975424155256564
1019339325744413
116186842231264
12220411108b511
13aa38c9301c5c
144ac057b6c433
152380d84cae0d
hex1196c9a4251d

19339325744413 has 2 divisors, whose sum is σ = 19339325744414. Its totient is φ = 19339325744412.

The previous prime is 19339325744363. The next prime is 19339325744419. The reversal of 19339325744413 is 31444752393391.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13212621596889 + 6126704147524 = 3634917^2 + 2475218^2 .

It is an emirp because it is prime and its reverse (31444752393391) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-19339325744413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (19339325744419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9669662872206 + 9669662872207.

It is an arithmetic number, because the mean of its divisors is an integer number (9669662872207).

Almost surely, 219339325744413 is an apocalyptic number.

It is an amenable number.

19339325744413 is a deficient number, since it is larger than the sum of its proper divisors (1).

19339325744413 is an equidigital number, since it uses as much as digits as its factorization.

19339325744413 is an evil number, because the sum of its binary digits is even.

The product of its digits is 29393280, while the sum is 58.

The spelling of 19339325744413 in words is "nineteen trillion, three hundred thirty-nine billion, three hundred twenty-five million, seven hundred forty-four thousand, four hundred thirteen".