1934124943 has 2 divisors, whose sum is σ = 1934124944. Its totient is φ = 1934124942.

The previous prime is 1934124859. The next prime is 1934124953. The reversal of 1934124943 is 3494214391.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1934124943 - 2¹⁷ = 1933993871 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1934124896 and 1934124905.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1934124953) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 967062471 + 967062472.

It is an arithmetic number, because the mean of its divisors is an integer number (967062472).

Almost surely, 2^1934124943 is an apocalyptic number.

1934124943 is a deficient number, since it is larger than the sum of its proper divisors (1).

1934124943 is an equidigital number, since it uses as much as digits as its factorization.

1934124943 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 93312, while the sum is 40.

The square root of 1934124943 is about 43978.6873724080. The cubic root of 1934124943 is about 1245.9334393204.

The spelling of 1934124943 in words is "one billion, nine hundred thirty-four million, one hundred twenty-four thousand, nine hundred forty-three".