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194431314017 is a prime number
BaseRepresentation
bin1011010100010100000…
…0100110100001100001
3200120212020211010102102
42311011000212201201
511141143404022032
6225153121500145
720022121620623
oct2650500464141
9616766733372
10194431314017
1175504453a86
12318227a1655
1315447709b05
1495a66a8c13
1550ce638362
hex2d45026861

194431314017 has 2 divisors, whose sum is σ = 194431314018. Its totient is φ = 194431314016.

The previous prime is 194431314013. The next prime is 194431314019. The reversal of 194431314017 is 710413134491.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121209118801 + 73222195216 = 348151^2 + 270596^2 .

It is an emirp because it is prime and its reverse (710413134491) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 194431314017 - 22 = 194431314013 is a prime.

Together with 194431314019, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (194431314013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 97215657008 + 97215657009.

It is an arithmetic number, because the mean of its divisors is an integer number (97215657009).

Almost surely, 2194431314017 is an apocalyptic number.

It is an amenable number.

194431314017 is a deficient number, since it is larger than the sum of its proper divisors (1).

194431314017 is an equidigital number, since it uses as much as digits as its factorization.

194431314017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36288, while the sum is 38.

The spelling of 194431314017 in words is "one hundred ninety-four billion, four hundred thirty-one million, three hundred fourteen thousand, seventeen".