Base | Representation |
---|---|
bin | 11100011011001010011… |
… | …110001001111101101110 |
3 | 20220201211200020111212111 |
4 | 130123022132021331232 |
5 | 224000340341231100 |
6 | 4053201132154234 |
7 | 261056615343541 |
oct | 34331236117556 |
9 | 6821750214774 |
10 | 1953312055150 |
11 | 6934388068a5 |
12 | 27669430897a |
13 | 112272a37ac1 |
14 | 6a77dd96858 |
15 | 35c242bc6ba |
hex | 1c6ca789f6e |
1953312055150 has 24 divisors (see below), whose sum is σ = 3653457424920. Its totient is φ = 776959875360.
The previous prime is 1953312055117. The next prime is 1953312055169. The reversal of 1953312055150 is 515502133591.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 109114629 + ... + 109132528.
It is an arithmetic number, because the mean of its divisors is an integer number (152227392705).
Almost surely, 21953312055150 is an apocalyptic number.
1953312055150 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1953312055150 is a deficient number, since it is larger than the sum of its proper divisors (1700145369770).
1953312055150 is a wasteful number, since it uses less digits than its factorization.
1953312055150 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 218247348 (or 218247343 counting only the distinct ones).
The product of its (nonzero) digits is 101250, while the sum is 40.
The spelling of 1953312055150 in words is "one trillion, nine hundred fifty-three billion, three hundred twelve million, fifty-five thousand, one hundred fifty".
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