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196342138343 = 1315103241411
BaseRepresentation
bin1011011011011011100…
…1110100010111100111
3200202210102101001121202
42312312321310113213
511204102041411333
6230110501233115
720120353432211
oct2666671642747
9622712331552
10196342138343
11762a502263a
123207670279b
13156905604b0
14970838d5b1
1551922835e8
hex2db6e745e7

196342138343 has 4 divisors (see below), whose sum is σ = 211445379768. Its totient is φ = 181238896920.

The previous prime is 196342138339. The next prime is 196342138357. The reversal of 196342138343 is 343831243691.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 196342138343 - 22 = 196342138339 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (196342138373) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7551620693 + ... + 7551620718.

It is an arithmetic number, because the mean of its divisors is an integer number (52861344942).

Almost surely, 2196342138343 is an apocalyptic number.

196342138343 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

196342138343 is a deficient number, since it is larger than the sum of its proper divisors (15103241425).

196342138343 is a wasteful number, since it uses less digits than its factorization.

196342138343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15103241424.

The product of its digits is 1119744, while the sum is 47.

The spelling of 196342138343 in words is "one hundred ninety-six billion, three hundred forty-two million, one hundred thirty-eight thousand, three hundred forty-three".

Divisors: 1 13 15103241411 196342138343