Base | Representation |
---|---|
bin | 11100101001001001111… |
… | …001100100010111111011 |
3 | 20222011121122021112120101 |
4 | 130221021321210113323 |
5 | 224222122210141111 |
6 | 4104123542540231 |
7 | 262131113111101 |
oct | 34511171442773 |
9 | 6864548245511 |
10 | 1968334849531 |
11 | 699847787646 |
12 | 279587437677 |
13 | 1137c820514b |
14 | 6b3a7231c71 |
15 | 363030d5bc1 |
hex | 1ca49e645fb |
1968334849531 has 2 divisors, whose sum is σ = 1968334849532. Its totient is φ = 1968334849530.
The previous prime is 1968334849519. The next prime is 1968334849543. The reversal of 1968334849531 is 1359484338691.
It is a balanced prime because it is at equal distance from previous prime (1968334849519) and next prime (1968334849543).
It is a cyclic number.
It is not a de Polignac number, because 1968334849531 - 211 = 1968334847483 is a prime.
It is a super-2 number, since 2×19683348495312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1968334849331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 984167424765 + 984167424766.
It is an arithmetic number, because the mean of its divisors is an integer number (984167424766).
Almost surely, 21968334849531 is an apocalyptic number.
1968334849531 is a deficient number, since it is larger than the sum of its proper divisors (1).
1968334849531 is an equidigital number, since it uses as much as digits as its factorization.
1968334849531 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 67184640, while the sum is 64.
The spelling of 1968334849531 in words is "one trillion, nine hundred sixty-eight billion, three hundred thirty-four million, eight hundred forty-nine thousand, five hundred thirty-one".
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