Base | Representation |
---|---|
bin | 1011100000110111000… |
… | …0010100111111101111 |
3 | 200220112222012221012020 |
4 | 2320031300110333233 |
5 | 11220043103041320 |
6 | 230511232441223 |
7 | 20201436016464 |
oct | 2701560247757 |
9 | 626488187166 |
10 | 197799268335 |
11 | 769825919a9 |
12 | 324026a9213 |
13 | 158633c27a6 |
14 | 9805ad366b |
15 | 522a160940 |
hex | 2e0dc14fef |
197799268335 has 12 divisors (see below), whose sum is σ = 316481585352. Its totient is φ = 105492024448.
The previous prime is 197799268283. The next prime is 197799268397. The reversal of 197799268335 is 533862997791.
It is not a de Polignac number, because 197799268335 - 225 = 197765713903 is a prime.
It is a super-2 number, since 2×1977992683352 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 197799268335.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1665079 + ... + 1779911.
It is an arithmetic number, because the mean of its divisors is an integer number (26373465446).
Almost surely, 2197799268335 is an apocalyptic number.
197799268335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
197799268335 is a deficient number, since it is larger than the sum of its proper divisors (118682317017).
197799268335 is an frugal number, since it uses more digits than its factorization.
197799268335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 229674 (or 114841 counting only the distinct ones).
The product of its digits is 154314720, while the sum is 69.
The spelling of 197799268335 in words is "one hundred ninety-seven billion, seven hundred ninety-nine million, two hundred sixty-eight thousand, three hundred thirty-five".
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