Base | Representation |
---|---|
bin | 11100110101011100101… |
… | …101101100110011000100 |
3 | 21000102200121110100120101 |
4 | 130311130231230303010 |
5 | 224431141031013200 |
6 | 4114145500413444 |
7 | 263106203025211 |
oct | 34653455546304 |
9 | 7012617410511 |
10 | 1981535407300 |
11 | 6a4401096019 |
12 | 280050247284 |
13 | 114b1ccc7c87 |
14 | 6bc9a486b08 |
15 | 36826e5226a |
hex | 1cd5cb6ccc4 |
1981535407300 has 18 divisors (see below), whose sum is σ = 4299931834058. Its totient is φ = 792614162880.
The previous prime is 1981535407207. The next prime is 1981535407301. The reversal of 1981535407300 is 37045351891.
It is a happy number.
It can be written as a sum of positive squares in 3 ways, for example, as 13889565316 + 1967645841984 = 117854^2 + 1402728^2 .
It is not an unprimeable number, because it can be changed into a prime (1981535407301) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 9907676937 + ... + 9907677136.
Almost surely, 21981535407300 is an apocalyptic number.
1981535407300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1981535407300 is an abundant number, since it is smaller than the sum of its proper divisors (2318396426758).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1981535407300 is a wasteful number, since it uses less digits than its factorization.
1981535407300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19815354087 (or 19815354080 counting only the distinct ones).
The product of its (nonzero) digits is 453600, while the sum is 46.
The spelling of 1981535407300 in words is "one trillion, nine hundred eighty-one billion, five hundred thirty-five million, four hundred seven thousand, three hundred".
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