1982402531 has 2 divisors, whose sum is σ = 1982402532. Its totient is φ = 1982402530.

The previous prime is 1982402507. The next prime is 1982402533. The reversal of 1982402531 is 1352042891.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1982402531 - 2¹⁸ = 1982140387 is a prime.

It is a super-2 number, since 2×1982402531² = 7859839589830411922, which contains 22 as substring.

Together with 1982402533, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1982402491 and 1982402500.

It is not a weakly prime, because it can be changed into another prime (1982402533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 991201265 + 991201266.

It is an arithmetic number, because the mean of its divisors is an integer number (991201266).

Almost surely, 2^1982402531 is an apocalyptic number.

1982402531 is a deficient number, since it is larger than the sum of its proper divisors (1).

1982402531 is an equidigital number, since it uses as much as digits as its factorization.

1982402531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 35.

The square root of 1982402531 is about 44524.1791726698. The cubic root of 1982402531 is about 1256.2149218657.

The spelling of 1982402531 in words is "one billion, nine hundred eighty-two million, four hundred two thousand, five hundred thirty-one".