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198304430561 is a prime number
BaseRepresentation
bin1011100010101111011…
…1010111100111100001
3200221212011202211111022
42320223313113213201
511222111413234221
6231033320055225
720220111563606
oct2705367274741
9627764684438
10198304430561
1177111754846
1232523904515
1315913c64453
149852c306ad
1552596984ab
hex2e2bdd79e1

198304430561 has 2 divisors, whose sum is σ = 198304430562. Its totient is φ = 198304430560.

The previous prime is 198304430539. The next prime is 198304430563. The reversal of 198304430561 is 165034403891.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 192748218961 + 5556211600 = 439031^2 + 74540^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-198304430561 is a prime.

Together with 198304430563, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (198304430563) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99152215280 + 99152215281.

It is an arithmetic number, because the mean of its divisors is an integer number (99152215281).

Almost surely, 2198304430561 is an apocalyptic number.

It is an amenable number.

198304430561 is a deficient number, since it is larger than the sum of its proper divisors (1).

198304430561 is an equidigital number, since it uses as much as digits as its factorization.

198304430561 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 311040, while the sum is 44.

The spelling of 198304430561 in words is "one hundred ninety-eight billion, three hundred four million, four hundred thirty thousand, five hundred sixty-one".