Base | Representation |
---|---|
bin | 11100110111000001101… |
… | …110001010000100000101 |
3 | 21000121001201011220101112 |
4 | 130313001232022010011 |
5 | 224443123341312424 |
6 | 4115025554134405 |
7 | 263166201035402 |
oct | 34670156120405 |
9 | 7017051156345 |
10 | 1983230025989 |
11 | 6a50a0713133 |
12 | 280443881405 |
13 | 11503010c024 |
14 | 6bdbb56b2a9 |
15 | 368c5ae160e |
hex | 1cdc1b8a105 |
1983230025989 has 2 divisors, whose sum is σ = 1983230025990. Its totient is φ = 1983230025988.
The previous prime is 1983230025947. The next prime is 1983230025991. The reversal of 1983230025989 is 9895200323891.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1945559097889 + 37670928100 = 1394833^2 + 194090^2 .
It is a cyclic number.
It is not a de Polignac number, because 1983230025989 - 212 = 1983230021893 is a prime.
Together with 1983230025991, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1983230025929) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 991615012994 + 991615012995.
It is an arithmetic number, because the mean of its divisors is an integer number (991615012995).
Almost surely, 21983230025989 is an apocalyptic number.
It is an amenable number.
1983230025989 is a deficient number, since it is larger than the sum of its proper divisors (1).
1983230025989 is an equidigital number, since it uses as much as digits as its factorization.
1983230025989 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8398080, while the sum is 59.
The spelling of 1983230025989 in words is "one trillion, nine hundred eighty-three billion, two hundred thirty million, twenty-five thousand, nine hundred eighty-nine".
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