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199673223149 is a prime number
BaseRepresentation
bin1011100111110101110…
…0111001011111101101
3201002101120101200221002
42321331130321133231
511232412321120044
6231421214050045
720266042251551
oct2717534713755
9632346350832
10199673223149
1177754368994
12328461a9925
1315aa17074aa
14994293b861
1552d992674e
hex2e7d7397ed

199673223149 has 2 divisors, whose sum is σ = 199673223150. Its totient is φ = 199673223148.

The previous prime is 199673223119. The next prime is 199673223151. The reversal of 199673223149 is 941322376991.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 195536418025 + 4136805124 = 442195^2 + 64318^2 .

It is a cyclic number.

It is not a de Polignac number, because 199673223149 - 28 = 199673222893 is a prime.

It is a super-3 number, since 3×1996732231493 (a number of 35 digits) contains 333 as substring.

Together with 199673223151, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 199673223094 and 199673223103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (199673223119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99836611574 + 99836611575.

It is an arithmetic number, because the mean of its divisors is an integer number (99836611575).

Almost surely, 2199673223149 is an apocalyptic number.

It is an amenable number.

199673223149 is a deficient number, since it is larger than the sum of its proper divisors (1).

199673223149 is an equidigital number, since it uses as much as digits as its factorization.

199673223149 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4408992, while the sum is 56.

The spelling of 199673223149 in words is "one hundred ninety-nine billion, six hundred seventy-three million, two hundred twenty-three thousand, one hundred forty-nine".