1998000493 has 2 divisors, whose sum is σ = 1998000494. Its totient is φ = 1998000492.

The previous prime is 1998000467. The next prime is 1998000509. The reversal of 1998000493 is 3940008991.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1682476324 + 315524169 = 41018^2 + 17763^2 .

It is a cyclic number.

It is not a de Polignac number, because 1998000493 - 2¹³ = 1997992301 is a prime.

It is a super-4 number, since 4×1998000493⁴ (a number of 38 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1998040493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 999000246 + 999000247.

It is an arithmetic number, because the mean of its divisors is an integer number (999000247).

Almost surely, 2^1998000493 is an apocalyptic number.

It is an amenable number.

1998000493 is a deficient number, since it is larger than the sum of its proper divisors (1).

1998000493 is an equidigital number, since it uses as much as digits as its factorization.

1998000493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69984, while the sum is 43.

The square root of 1998000493 is about 44698.9987919193. The cubic root of 1998000493 is about 1259.5010397351.

The spelling of 1998000493 in words is "one billion, nine hundred ninety-eight million, four hundred ninety-three", and thus it is an aban number.