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199903499384447 is a prime number
BaseRepresentation
bin101101011100111110101001…
…000100011111011001111111
3222012210120212120200212100002
4231130332221010133121333
5202200204331320300242
61545054222210224515
760051360032523155
oct5534765104373177
9865716776625302
10199903499384447
1158771663a24611
121a50677958513b
138770a85761831
1437515496413d5
151819e3718e432
hexb5cfa911f67f

199903499384447 has 2 divisors, whose sum is σ = 199903499384448. Its totient is φ = 199903499384446.

The previous prime is 199903499384441. The next prime is 199903499384453. The reversal of 199903499384447 is 744483994309991.

It is a balanced prime because it is at equal distance from previous prime (199903499384441) and next prime (199903499384453).

It is a cyclic number.

It is not a de Polignac number, because 199903499384447 - 24 = 199903499384431 is a prime.

It is a super-2 number, since 2×1999034993844472 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (199903499384441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99951749692223 + 99951749692224.

It is an arithmetic number, because the mean of its divisors is an integer number (99951749692224).

Almost surely, 2199903499384447 is an apocalyptic number.

199903499384447 is a deficient number, since it is larger than the sum of its proper divisors (1).

199903499384447 is an equidigital number, since it uses as much as digits as its factorization.

199903499384447 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7618738176, while the sum is 83.

The spelling of 199903499384447 in words is "one hundred ninety-nine trillion, nine hundred three billion, four hundred ninety-nine million, three hundred eighty-four thousand, four hundred forty-seven".