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1999227647 is a prime number
BaseRepresentation
bin111011100101001…
…1100101011111111
312011022220021202102
41313022130223333
513043300241042
6530214215315
7100354104014
oct16712345377
95138807672
101999227647
1193656a35a
1247965453b
1325b266951
1414d73770b
15ba7adb32
hex7729caff

1999227647 has 2 divisors, whose sum is σ = 1999227648. Its totient is φ = 1999227646.

The previous prime is 1999227613. The next prime is 1999227649. The reversal of 1999227647 is 7467229991.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1999227647 is a prime.

It is a super-2 number, since 2×19992276472 = 7993822369058313218, which contains 22 as substring.

Together with 1999227649, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1999227592 and 1999227601.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1999227649) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 999613823 + 999613824.

It is an arithmetic number, because the mean of its divisors is an integer number (999613824).

Almost surely, 21999227647 is an apocalyptic number.

1999227647 is a deficient number, since it is larger than the sum of its proper divisors (1).

1999227647 is an equidigital number, since it uses as much as digits as its factorization.

1999227647 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3429216, while the sum is 56.

The square root of 1999227647 is about 44712.7235471068. The cubic root of 1999227647 is about 1259.7588450461.

The spelling of 1999227647 in words is "one billion, nine hundred ninety-nine million, two hundred twenty-seven thousand, six hundred forty-seven".