Base | Representation |
---|---|
bin | 1011101001000011101… |
… | …1011101000000001011 |
3 | 201010020100021200111211 |
4 | 2322100323131000023 |
5 | 11234100000000021 |
6 | 231513450033551 |
7 | 20310120644020 |
oct | 2722073350013 |
9 | 633210250454 |
10 | 200000000011 |
11 | 77901871209 |
12 | 329177188b7 |
13 | 15b2431c196 |
14 | 99740c1547 |
15 | 53084743e1 |
hex | 2e90edd00b |
200000000011 has 32 divisors (see below), whose sum is σ = 243071055360. Its totient is φ = 160643298816.
The previous prime is 199999999949. The next prime is 200000000041. The reversal of 200000000011 is 110000000002.
It is not a de Polignac number, because 200000000011 - 29 = 199999999499 is a prime.
It is not an unprimeable number, because it can be changed into a prime (200000000041) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 27270301 + ... + 27277633.
It is an arithmetic number, because the mean of its divisors is an integer number (7595970480).
Almost surely, 2200000000011 is an apocalyptic number.
200000000011 is a deficient number, since it is larger than the sum of its proper divisors (43071055349).
200000000011 is a wasteful number, since it uses less digits than its factorization.
200000000011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8323.
The product of its (nonzero) digits is 2, while the sum is 4.
Adding to 200000000011 its reverse (110000000002), we get a palindrome (310000000013).
Subtracting from 200000000011 its reverse (110000000002), we obtain a palindrome (90000000009).
It can be divided in two parts, 20000000001 and 1, that added together give a palindrome (20000000002).
The spelling of 200000000011 in words is "two hundred billion, eleven", and thus it is an aban number.
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