110000000002 has 4 divisors (see below), whose sum is σ = 165000000006. Its totient is φ = 55000000000.

The previous prime is 109999999987. The next prime is 110000000003. The reversal of 110000000002 is 200000000011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 101404670481 + 8595329521 = 318441^2 + 92711^2 .

It is a junction number, because it is equal to n+sod(n) for n = 109999999919 and 110000000000.

It is not an unprimeable number, because it can be changed into a prime (110000000003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27499999999 + ... + 27500000002.

Almost surely, 2^110000000002 is an apocalyptic number.

110000000002 is a deficient number, since it is larger than the sum of its proper divisors (55000000004).

110000000002 is an equidigital number, since it uses as much as digits as its factorization.

110000000002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55000000003.

The product of its (nonzero) digits is 2, while the sum is 4.

Adding to 110000000002 its reverse (200000000011), we get a palindrome (310000000013).

Subtracting 110000000002 from its reverse (200000000011), we obtain a palindrome (90000000009).

The spelling of 110000000002 in words is "one hundred ten billion, two", and thus it is an aban number.