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2000001253 = 11711707943
BaseRepresentation
bin111011100110101…
…1001100011100101
312011101100120221111
41313031121203211
513044000020003
6530242545021
7100363505305
oct16715314345
95141316844
102000001253
11936a485a8
12479968171
1325b477ac3
1414d899605
15ba8b2e6d
hex773598e5

2000001253 has 4 divisors (see below), whose sum is σ = 2001710368. Its totient is φ = 1998292140.

The previous prime is 2000001247. The next prime is 2000001257. The reversal of 2000001253 is 3521000002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2000001253 - 29 = 2000000741 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2000001257) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 852801 + ... + 855142.

It is an arithmetic number, because the mean of its divisors is an integer number (500427592).

Almost surely, 22000001253 is an apocalyptic number.

It is an amenable number.

2000001253 is a deficient number, since it is larger than the sum of its proper divisors (1709115).

2000001253 is a wasteful number, since it uses less digits than its factorization.

2000001253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1709114.

The product of its (nonzero) digits is 60, while the sum is 13.

The square root of 2000001253 is about 44721.3735589595. The cubic root of 2000001253 is about 1259.9213130083.

Adding to 2000001253 its reverse (3521000002), we get a palindrome (5521001255).

The spelling of 2000001253 in words is "two billion, one thousand, two hundred fifty-three".

Divisors: 1 1171 1707943 2000001253