Search a number
-
+
200001001003143 = 366667000334381
BaseRepresentation
bin101101011110011001011100…
…100111101001100010000111
3222020010220112122012021201220
4231132121130213221202013
5202203304022224100033
61545211105204251423
760061411151564154
oct5536313447514207
9866126478167656
10200001001003143
11587a9a4806187a
121a52164a6a0b73
13877a02378a832
14375615895322b
15181c741dbcbb3
hexb5e65c9e9887

200001001003143 has 4 divisors (see below), whose sum is σ = 266668001337528. Its totient is φ = 133334000668760.

The previous prime is 200001001003109. The next prime is 200001001003157. The reversal of 200001001003143 is 341300100100002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200001001003143 - 210 = 200001001002119 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200001001001143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33333500167188 + ... + 33333500167193.

It is an arithmetic number, because the mean of its divisors is an integer number (66667000334382).

Almost surely, 2200001001003143 is an apocalyptic number.

200001001003143 is a deficient number, since it is larger than the sum of its proper divisors (66667000334385).

200001001003143 is an equidigital number, since it uses as much as digits as its factorization.

200001001003143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66667000334384.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 200001001003143 its reverse (341300100100002), we get a palindrome (541301101103145).

The spelling of 200001001003143 in words is "two hundred trillion, one billion, one million, three thousand, one hundred forty-three".

Divisors: 1 3 66667000334381 200001001003143