2000013000043 has 2 divisors, whose sum is σ = 2000013000044. Its totient is φ = 2000013000042.

The previous prime is 2000012999939. The next prime is 2000013000049. The reversal of 2000013000043 is 3400003100002.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2000013000043 - 2³³ = 1991423065451 is a prime.

It is a super-3 number, since 3×2000013000043³ (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 2000012999987 and 2000013000032.

It is not a weakly prime, because it can be changed into another prime (2000013000049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000006500021 + 1000006500022.

It is an arithmetic number, because the mean of its divisors is an integer number (1000006500022).

Almost surely, 2^{2000013000043} is an apocalyptic number.

2000013000043 is a deficient number, since it is larger than the sum of its proper divisors (1).

2000013000043 is an equidigital number, since it uses as much as digits as its factorization.

2000013000043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 13.

Adding to 2000013000043 its reverse (3400003100002), we get a palindrome (5400016100045).

The spelling of 2000013000043 in words is "two trillion, thirteen million, forty-three", and thus it is an aban number and an uban number.