200011000101113 has 4 divisors (see below), whose sum is σ = 200011087974528. Its totient is φ = 200010912227700.

The previous prime is 200011000101089. The next prime is 200011000101197. The reversal of 200011000101113 is 311101000110002.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200011000101113 - 2³⁴ = 199993820231929 is a prime.

It is a super-2 number, since 2×200011000101113² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200011000101094 and 200011000101103.

It is not an unprimeable number, because it can be changed into a prime (200011000101313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40429181 + ... + 45105882.

It is an arithmetic number, because the mean of its divisors is an integer number (50002771993632).

Almost surely, 2^{200011000101113} is an apocalyptic number.

It is an amenable number.

200011000101113 is a deficient number, since it is larger than the sum of its proper divisors (87873415).

200011000101113 is an equidigital number, since it uses as much as digits as its factorization.

200011000101113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 87873414.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 200011000101113 its reverse (311101000110002), we get a palindrome (511112000211115).

The spelling of 200011000101113 in words is "two hundred trillion, eleven billion, one hundred one thousand, one hundred thirteen".