Base | Representation |
---|---|
bin | 111011100110111… |
… | …0100011011101101 |
3 | 12011101120011221211 |
4 | 1313031310123231 |
5 | 13044012030331 |
6 | 530245154421 |
7 | 100364444254 |
oct | 16715643355 |
9 | 5141504854 |
10 | 2000111341 |
11 | 937013288 |
12 | 4799bba11 |
13 | 25b4b5c47 |
14 | 14d8c779b |
15 | ba8d58b1 |
hex | 773746ed |
2000111341 has 4 divisors (see below), whose sum is σ = 2024209152. Its totient is φ = 1976013532.
The previous prime is 2000111339. The next prime is 2000111357. The reversal of 2000111341 is 1431110002.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2000111341 - 21 = 2000111339 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2000111941) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12048781 + ... + 12048946.
It is an arithmetic number, because the mean of its divisors is an integer number (506052288).
Almost surely, 22000111341 is an apocalyptic number.
It is an amenable number.
2000111341 is a deficient number, since it is larger than the sum of its proper divisors (24097811).
2000111341 is an equidigital number, since it uses as much as digits as its factorization.
2000111341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24097810.
The product of its (nonzero) digits is 24, while the sum is 13.
The square root of 2000111341 is about 44722.6043628946. The cubic root of 2000111341 is about 1259.9444296060.
Adding to 2000111341 its reverse (1431110002), we get a palindrome (3431221343).
The spelling of 2000111341 in words is "two billion, one hundred eleven thousand, three hundred forty-one".
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