Base | Representation |
---|---|
bin | 1001000110000110111111… |
… | …10001110101001001100111 |
3 | 2121211002101120220201002021 |
4 | 10203003133301311021213 |
5 | 10110144244230041403 |
6 | 110312215540524011 |
7 | 4133014310561506 |
oct | 443033761651147 |
9 | 77732346821067 |
10 | 20001122112103 |
11 | 6411479005510 |
12 | 22b04273b0607 |
13 | b211369072b2 |
14 | 4d20b92b483d |
15 | 24a41d6388bd |
hex | 1230dfc75267 |
20001122112103 has 8 divisors (see below), whose sum is σ = 21991212288000. Its totient is φ = 18039666327480.
The previous prime is 20001122112091. The next prime is 20001122112109. The reversal of 20001122112103 is 30121122110002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 20001122112103 - 217 = 20001121981031 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20001122112109) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7158596353 + ... + 7158599146.
It is an arithmetic number, because the mean of its divisors is an integer number (2748901536000).
Almost surely, 220001122112103 is an apocalyptic number.
20001122112103 is a deficient number, since it is larger than the sum of its proper divisors (1990090175897).
20001122112103 is a wasteful number, since it uses less digits than its factorization.
20001122112103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14317195637.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 20001122112103 its reverse (30121122110002), we get a palindrome (50122244222105).
The spelling of 20001122112103 in words is "twenty trillion, one billion, one hundred twenty-two million, one hundred twelve thousand, one hundred three".
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