Base | Representation |
---|---|
bin | 1011101001000110011… |
… | …0100100100011000111 |
3 | 201010021010112221110011 |
4 | 2322101212210203013 |
5 | 11234110343144421 |
6 | 231514532211051 |
7 | 20310316011454 |
oct | 2722146444307 |
9 | 633233487404 |
10 | 200011303111 |
11 | 77908191414 |
12 | 3291b469a87 |
13 | 15b26778bc9 |
14 | 99757c482b |
15 | 53094584e1 |
hex | 2e919a48c7 |
200011303111 has 16 divisors (see below), whose sum is σ = 202539924000. Its totient is φ = 197502012288.
The previous prime is 200011302989. The next prime is 200011303117. The reversal of 200011303111 is 111303110002.
It is a cyclic number.
It is not a de Polignac number, because 200011303111 - 225 = 199977748679 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 200011303091 and 200011303100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200011303117) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17895721 + ... + 17906893.
It is an arithmetic number, because the mean of its divisors is an integer number (12658745250).
Almost surely, 2200011303111 is an apocalyptic number.
200011303111 is a deficient number, since it is larger than the sum of its proper divisors (2528620889).
200011303111 is a wasteful number, since it uses less digits than its factorization.
200011303111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12018.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 200011303111 its reverse (111303110002), we get a palindrome (311314413113).
The spelling of 200011303111 in words is "two hundred billion, eleven million, three hundred three thousand, one hundred eleven".
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