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200011303111 = 14931737911173
BaseRepresentation
bin1011101001000110011…
…0100100100011000111
3201010021010112221110011
42322101212210203013
511234110343144421
6231514532211051
720310316011454
oct2722146444307
9633233487404
10200011303111
1177908191414
123291b469a87
1315b26778bc9
1499757c482b
1553094584e1
hex2e919a48c7

200011303111 has 16 divisors (see below), whose sum is σ = 202539924000. Its totient is φ = 197502012288.

The previous prime is 200011302989. The next prime is 200011303117. The reversal of 200011303111 is 111303110002.

It is a cyclic number.

It is not a de Polignac number, because 200011303111 - 225 = 199977748679 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200011303091 and 200011303100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200011303117) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17895721 + ... + 17906893.

It is an arithmetic number, because the mean of its divisors is an integer number (12658745250).

Almost surely, 2200011303111 is an apocalyptic number.

200011303111 is a deficient number, since it is larger than the sum of its proper divisors (2528620889).

200011303111 is a wasteful number, since it uses less digits than its factorization.

200011303111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12018.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 200011303111 its reverse (111303110002), we get a palindrome (311314413113).

The spelling of 200011303111 in words is "two hundred billion, eleven million, three hundred three thousand, one hundred eleven".

Divisors: 1 149 317 379 11173 47233 56471 120143 1664777 3541841 4234567 17901307 527734309 630950483 1342357739 200011303111