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2000114023 is a prime number
BaseRepresentation
bin111011100110111…
…0101000101100111
312011101120022122011
41313031311011213
513044012122043
6530245215051
7100364455135
oct16715650547
95141508564
102000114023
119370152a6
12479a01487
1325b4b722b
1414d8c8755
15ba8d659d
hex77375167

2000114023 has 2 divisors, whose sum is σ = 2000114024. Its totient is φ = 2000114022.

The previous prime is 2000114003. The next prime is 2000114027. The reversal of 2000114023 is 3204110002.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2000114023 is a prime.

It is a super-2 number, since 2×20001140232 = 8000912210002489058, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2000113994 and 2000114012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2000114027) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000057011 + 1000057012.

It is an arithmetic number, because the mean of its divisors is an integer number (1000057012).

Almost surely, 22000114023 is an apocalyptic number.

2000114023 is a deficient number, since it is larger than the sum of its proper divisors (1).

2000114023 is an equidigital number, since it uses as much as digits as its factorization.

2000114023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 13.

The square root of 2000114023 is about 44722.6343477215. The cubic root of 2000114023 is about 1259.9449927695.

Adding to 2000114023 its reverse (3204110002), we get a palindrome (5204224025).

The spelling of 2000114023 in words is "two billion, one hundred fourteen thousand, twenty-three".