Base | Representation |
---|---|
bin | 11101000110110000000… |
… | …101111111010001100111 |
3 | 21002012122101122101211100 |
4 | 131012300011333101213 |
5 | 230232213210340201 |
6 | 4130501215411143 |
7 | 264334456533234 |
oct | 35066005772147 |
9 | 7065571571740 |
10 | 2000114152551 |
11 | 701275329339 |
12 | 283776223ab3 |
13 | 1167c10c1868 |
14 | 6cb3dac678b |
15 | 3706302a886 |
hex | 1d1b017f467 |
2000114152551 has 12 divisors (see below), whose sum is σ = 2889099986760. Its totient is φ = 1333388106960.
The previous prime is 2000114152483. The next prime is 2000114152607. The reversal of 2000114152551 is 1552514110002.
It is a happy number.
2000114152551 is a `hidden beast` number, since 20 + 0 + 0 + 1 + 1 + 41 + 52 + 551 = 666.
It is not a de Polignac number, because 2000114152551 - 29 = 2000114152039 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2000114152151) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1172580 + ... + 2318441.
It is an arithmetic number, because the mean of its divisors is an integer number (240758332230).
Almost surely, 22000114152551 is an apocalyptic number.
2000114152551 is a deficient number, since it is larger than the sum of its proper divisors (888985834209).
2000114152551 is a wasteful number, since it uses less digits than its factorization.
2000114152551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3554686 (or 3554683 counting only the distinct ones).
The product of its (nonzero) digits is 2000, while the sum is 27.
Adding to 2000114152551 its reverse (1552514110002), we get a palindrome (3552628262553).
The spelling of 2000114152551 in words is "two trillion, one hundred fourteen million, one hundred fifty-two thousand, five hundred fifty-one".
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