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2000121100007 is a prime number
BaseRepresentation
bin11101000110110000100…
…000011111011011100111
321002012122212201100221112
4131012300200133123213
5230232222000200012
64130502024335235
7264334602560222
oct35066040373347
97065585640845
102000121100007
11701279244038
1228377861451b
131167c2684b94
146cb409b45b9
153706394e122
hex1d1b081f6e7

2000121100007 has 2 divisors, whose sum is σ = 2000121100008. Its totient is φ = 2000121100006.

The previous prime is 2000121099959. The next prime is 2000121100009. The reversal of 2000121100007 is 7000011210002.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2000121100007 - 28 = 2000121099751 is a prime.

Together with 2000121100009, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 2000121099964 and 2000121100000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2000121100009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000060550003 + 1000060550004.

It is an arithmetic number, because the mean of its divisors is an integer number (1000060550004).

Almost surely, 22000121100007 is an apocalyptic number.

2000121100007 is a deficient number, since it is larger than the sum of its proper divisors (1).

2000121100007 is an equidigital number, since it uses as much as digits as its factorization.

2000121100007 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28, while the sum is 14.

Adding to 2000121100007 its reverse (7000011210002), we get a palindrome (9000132310009).

The spelling of 2000121100007 in words is "two trillion, one hundred twenty-one million, one hundred thousand, seven".