Base | Representation |
---|---|
bin | 11101000110110000100… |
… | …000011111011011100111 |
3 | 21002012122212201100221112 |
4 | 131012300200133123213 |
5 | 230232222000200012 |
6 | 4130502024335235 |
7 | 264334602560222 |
oct | 35066040373347 |
9 | 7065585640845 |
10 | 2000121100007 |
11 | 701279244038 |
12 | 28377861451b |
13 | 1167c2684b94 |
14 | 6cb409b45b9 |
15 | 3706394e122 |
hex | 1d1b081f6e7 |
2000121100007 has 2 divisors, whose sum is σ = 2000121100008. Its totient is φ = 2000121100006.
The previous prime is 2000121099959. The next prime is 2000121100009. The reversal of 2000121100007 is 7000011210002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2000121100007 - 28 = 2000121099751 is a prime.
Together with 2000121100009, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 2000121099964 and 2000121100000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2000121100009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000060550003 + 1000060550004.
It is an arithmetic number, because the mean of its divisors is an integer number (1000060550004).
Almost surely, 22000121100007 is an apocalyptic number.
2000121100007 is a deficient number, since it is larger than the sum of its proper divisors (1).
2000121100007 is an equidigital number, since it uses as much as digits as its factorization.
2000121100007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28, while the sum is 14.
Adding to 2000121100007 its reverse (7000011210002), we get a palindrome (9000132310009).
The spelling of 2000121100007 in words is "two trillion, one hundred twenty-one million, one hundred thousand, seven".
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