Base | Representation |
---|---|
bin | 10010101000001010… |
… | …101011100000111111 |
3 | 1220121220212022210022 |
4 | 102220022223200333 |
5 | 311430304204101 |
6 | 13104412002355 |
7 | 1305435513263 |
oct | 225012534077 |
9 | 56556768708 |
10 | 20001241151 |
11 | 85341a7571 |
12 | 3a624603bb |
13 | 1b69a20848 |
14 | d7a52a0a3 |
15 | 7c0e13a1b |
hex | 4a82ab83f |
20001241151 has 2 divisors, whose sum is σ = 20001241152. Its totient is φ = 20001241150.
The previous prime is 20001241097. The next prime is 20001241231. The reversal of 20001241151 is 15114210002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20001241151 - 214 = 20001224767 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20001241451) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10000620575 + 10000620576.
It is an arithmetic number, because the mean of its divisors is an integer number (10000620576).
Almost surely, 220001241151 is an apocalyptic number.
20001241151 is a deficient number, since it is larger than the sum of its proper divisors (1).
20001241151 is an equidigital number, since it uses as much as digits as its factorization.
20001241151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80, while the sum is 17.
Adding to 20001241151 its reverse (15114210002), we get a palindrome (35115451153).
The spelling of 20001241151 in words is "twenty billion, one million, two hundred forty-one thousand, one hundred fifty-one".
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