Base | Representation |
---|---|
bin | 1011101001000110110… |
… | …1011011010001000111 |
3 | 201010021020221020110102 |
4 | 2322101231123101013 |
5 | 11234111323200403 |
6 | 231515034514315 |
7 | 20310340204505 |
oct | 2722155332107 |
9 | 633236836412 |
10 | 200013100103 |
11 | 779091a9533 |
12 | 3291bb9599b |
13 | 15b26c57b0b |
14 | 9975b31675 |
15 | 53096b0b88 |
hex | 2e91b5b447 |
200013100103 has 4 divisors (see below), whose sum is σ = 200022237168. Its totient is φ = 200003963040.
The previous prime is 200013100099. The next prime is 200013100151. The reversal of 200013100103 is 301001310002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 200013100103 - 22 = 200013100099 is a prime.
It is a super-2 number, since 2×2000131001032 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200013100163) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4535618 + ... + 4579503.
It is an arithmetic number, because the mean of its divisors is an integer number (50005559292).
Almost surely, 2200013100103 is an apocalyptic number.
200013100103 is a deficient number, since it is larger than the sum of its proper divisors (9137065).
200013100103 is an equidigital number, since it uses as much as digits as its factorization.
200013100103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9137064.
The product of its (nonzero) digits is 18, while the sum is 11.
Adding to 200013100103 its reverse (301001310002), we get a palindrome (501014410105).
The spelling of 200013100103 in words is "two hundred billion, thirteen million, one hundred thousand, one hundred three".
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