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2000133100243 is a prime number
BaseRepresentation
bin11101000110110001001…
…110010001001011010011
321002012200201022001011201
4131012301032101023103
5230232233033201433
64130503133452031
7264335106560305
oct35066116211323
97065621261151
102000133100243
11701284a9aa93
12283780641017
131167c4cc7005
146cb42419975
1537064a1ea7d
hex1d1b13912d3

2000133100243 has 2 divisors, whose sum is σ = 2000133100244. Its totient is φ = 2000133100242.

The previous prime is 2000133100241. The next prime is 2000133100271. The reversal of 2000133100243 is 3420013310002.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2000133100243 - 21 = 2000133100241 is a prime.

Together with 2000133100241, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 2000133100243.

It is not a weakly prime, because it can be changed into another prime (2000133100241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000066550121 + 1000066550122.

It is an arithmetic number, because the mean of its divisors is an integer number (1000066550122).

Almost surely, 22000133100243 is an apocalyptic number.

2000133100243 is a deficient number, since it is larger than the sum of its proper divisors (1).

2000133100243 is an equidigital number, since it uses as much as digits as its factorization.

2000133100243 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 2000133100243 its reverse (3420013310002), we get a palindrome (5420146410245).

The spelling of 2000133100243 in words is "two trillion, one hundred thirty-three million, one hundred thousand, two hundred forty-three".