Base | Representation |
---|---|
bin | 11101000110110001001… |
… | …110010001001011010011 |
3 | 21002012200201022001011201 |
4 | 131012301032101023103 |
5 | 230232233033201433 |
6 | 4130503133452031 |
7 | 264335106560305 |
oct | 35066116211323 |
9 | 7065621261151 |
10 | 2000133100243 |
11 | 701284a9aa93 |
12 | 283780641017 |
13 | 1167c4cc7005 |
14 | 6cb42419975 |
15 | 37064a1ea7d |
hex | 1d1b13912d3 |
2000133100243 has 2 divisors, whose sum is σ = 2000133100244. Its totient is φ = 2000133100242.
The previous prime is 2000133100241. The next prime is 2000133100271. The reversal of 2000133100243 is 3420013310002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2000133100243 - 21 = 2000133100241 is a prime.
Together with 2000133100241, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 2000133100243.
It is not a weakly prime, because it can be changed into another prime (2000133100241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000066550121 + 1000066550122.
It is an arithmetic number, because the mean of its divisors is an integer number (1000066550122).
Almost surely, 22000133100243 is an apocalyptic number.
2000133100243 is a deficient number, since it is larger than the sum of its proper divisors (1).
2000133100243 is an equidigital number, since it uses as much as digits as its factorization.
2000133100243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 2000133100243 its reverse (3420013310002), we get a palindrome (5420146410245).
The spelling of 2000133100243 in words is "two trillion, one hundred thirty-three million, one hundred thousand, two hundred forty-three".
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