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2000230021311 = 3666743340437
BaseRepresentation
bin11101000110110110111…
…111111111100010111111
321002012221110200010212220
4131012312333333202333
5230232432341140221
64130520515100423
7264340364440104
oct35066677774277
97065843603786
102000230021311
11701324779245
122837a8ba1713
1311680c100262
146cb51248aab
153706d2b70c6
hex1d1b6fff8bf

2000230021311 has 4 divisors (see below), whose sum is σ = 2666973361752. Its totient is φ = 1333486680872.

The previous prime is 2000230021297. The next prime is 2000230021343. The reversal of 2000230021311 is 1131200320002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2000230021311 - 29 = 2000230020799 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2000230071311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 333371670216 + ... + 333371670221.

It is an arithmetic number, because the mean of its divisors is an integer number (666743340438).

Almost surely, 22000230021311 is an apocalyptic number.

2000230021311 is a deficient number, since it is larger than the sum of its proper divisors (666743340441).

2000230021311 is an equidigital number, since it uses as much as digits as its factorization.

2000230021311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 666743340440.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 2000230021311 its reverse (1131200320002), we get a palindrome (3131430341313).

The spelling of 2000230021311 in words is "two trillion, two hundred thirty million, twenty-one thousand, three hundred eleven".

Divisors: 1 3 666743340437 2000230021311