2000315411 has 4 divisors (see below), whose sum is σ = 2005458000. Its totient is φ = 1995172824.

The previous prime is 2000315399. The next prime is 2000315461. The reversal of 2000315411 is 1145130002.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1145130002 = 2 ⋅572565001.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2000315411 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2000315411.

It is not an unprimeable number, because it can be changed into a prime (2000315461) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2570711 + ... + 2571488.

It is an arithmetic number, because the mean of its divisors is an integer number (501364500).

Almost surely, 2^2000315411 is an apocalyptic number.

2000315411 is a deficient number, since it is larger than the sum of its proper divisors (5142589).

2000315411 is an equidigital number, since it uses as much as digits as its factorization.

2000315411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5142588.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 2000315411 is about 44724.8858131578. The cubic root of 2000315411 is about 1259.9872785732.

Adding to 2000315411 its reverse (1145130002), we get a palindrome (3145445413).

The spelling of 2000315411 in words is "two billion, three hundred fifteen thousand, four hundred eleven".