Base | Representation |
---|---|
bin | 11101000110111100011… |
… | …000111000110001001111 |
3 | 21002020011202210112201112 |
4 | 131012330120320301033 |
5 | 230233124012330411 |
6 | 4130533505002235 |
7 | 264342543066521 |
oct | 35067430706117 |
9 | 7066152715645 |
10 | 2000320433231 |
11 | 70137081103a |
12 | 28381332337b |
13 | 116824a67833 |
14 | 6cb5d261a11 |
15 | 370761c5b8b |
hex | 1d1bc638c4f |
2000320433231 has 2 divisors, whose sum is σ = 2000320433232. Its totient is φ = 2000320433230.
The previous prime is 2000320433171. The next prime is 2000320433273. The reversal of 2000320433231 is 1323340230002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2000320433231 - 210 = 2000320432207 is a prime.
It is a super-3 number, since 3×20003204332313 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 2000320433197 and 2000320433206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2000320433431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000160216615 + 1000160216616.
It is an arithmetic number, because the mean of its divisors is an integer number (1000160216616).
Almost surely, 22000320433231 is an apocalyptic number.
2000320433231 is a deficient number, since it is larger than the sum of its proper divisors (1).
2000320433231 is an equidigital number, since it uses as much as digits as its factorization.
2000320433231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 23.
Adding to 2000320433231 its reverse (1323340230002), we get a palindrome (3323660663233).
The spelling of 2000320433231 in words is "two trillion, three hundred twenty million, four hundred thirty-three thousand, two hundred thirty-one".
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