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200032413424111 is a prime number
BaseRepresentation
bin101101011110110110101100…
…111100100001100111101111
3222020020220121211012121102201
4231132312230330201213233
5202204312340314032421
61545233342213402331
760063602452010332
oct5536665474414757
9866226554177381
10200032413424111
11588112a75a8664
121a5277566393a7
13877cc8b65cb88
1437578987c4619
15181d47e9e1b91
hexb5edacf219ef

200032413424111 has 2 divisors, whose sum is σ = 200032413424112. Its totient is φ = 200032413424110.

The previous prime is 200032413424061. The next prime is 200032413424133. The reversal of 200032413424111 is 111424314230002.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 200032413424111 - 223 = 200032405035503 is a prime.

It is a super-2 number, since 2×2000324134241112 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 200032413424111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200032413422111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100016206712055 + 100016206712056.

It is an arithmetic number, because the mean of its divisors is an integer number (100016206712056).

Almost surely, 2200032413424111 is an apocalyptic number.

200032413424111 is a deficient number, since it is larger than the sum of its proper divisors (1).

200032413424111 is an equidigital number, since it uses as much as digits as its factorization.

200032413424111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 200032413424111 its reverse (111424314230002), we get a palindrome (311456727654113).

The spelling of 200032413424111 in words is "two hundred trillion, thirty-two billion, four hundred thirteen million, four hundred twenty-four thousand, one hundred eleven".