200033114400131 has 4 divisors (see below), whose sum is σ = 211799768188392. Its totient is φ = 188266460611872.

The previous prime is 200033114400107. The next prime is 200033114400169. The reversal of 200033114400131 is 131004411330002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200033114400131 - 2³⁸ = 199758236493187 is a prime.

It is a super-2 number, since 2×200033114400131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200033114400097 and 200033114400106.

It is not an unprimeable number, because it can be changed into a prime (200033114400181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5883326894105 + ... + 5883326894138.

It is an arithmetic number, because the mean of its divisors is an integer number (52949942047098).

Almost surely, 2^{200033114400131} is an apocalyptic number.

200033114400131 is a deficient number, since it is larger than the sum of its proper divisors (11766653788261).

200033114400131 is a wasteful number, since it uses less digits than its factorization.

200033114400131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11766653788260.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 200033114400131 its reverse (131004411330002), we get a palindrome (331037525730133).

The spelling of 200033114400131 in words is "two hundred trillion, thirty-three billion, one hundred fourteen million, four hundred thousand, one hundred thirty-one".