200042000113 has 4 divisors (see below), whose sum is σ = 200872050148. Its totient is φ = 199211950080.

The previous prime is 200042000077. The next prime is 200042000153. The reversal of 200042000113 is 311000240002.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 311000240002 = 2 ⋅155500120001.

It can be written as a sum of positive squares in 2 ways, for example, as 141260967409 + 58781032704 = 375847^2 + 242448^2 .

It is a cyclic number.

It is not a de Polignac number, because 200042000113 - 2²¹ = 200039902961 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200042000093 and 200042000102.

It is not an unprimeable number, because it can be changed into a prime (200042000153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 415024656 + ... + 415025137.

It is an arithmetic number, because the mean of its divisors is an integer number (50218012537).

Almost surely, 2^200042000113 is an apocalyptic number.

It is an amenable number.

200042000113 is a deficient number, since it is larger than the sum of its proper divisors (830050035).

200042000113 is an equidigital number, since it uses as much as digits as its factorization.

200042000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 830050034.

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 200042000113 its reverse (311000240002), we get a palindrome (511042240115).

The spelling of 200042000113 in words is "two hundred billion, forty-two million, one hundred thirteen", and thus it is an aban number.