Base | Representation |
---|---|
bin | 11101000111000010010… |
… | …100101110000011001001 |
3 | 21002020102201011021012022 |
4 | 131013002110232003021 |
5 | 230233330010112131 |
6 | 4130551423054225 |
7 | 264345162323444 |
oct | 35070224560311 |
9 | 7066381137168 |
10 | 2000420004041 |
11 | 701411a3a068 |
12 | 283840741375 |
13 | 11683c58ab84 |
14 | 6cb6c58065b |
15 | 3707ece337b |
hex | 1d1c252e0c9 |
2000420004041 has 2 divisors, whose sum is σ = 2000420004042. Its totient is φ = 2000420004040.
The previous prime is 2000420004029. The next prime is 2000420004043. The reversal of 2000420004041 is 1404000240002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1959006126025 + 41413878016 = 1399645^2 + 203504^2 .
It is a cyclic number.
It is not a de Polignac number, because 2000420004041 - 222 = 2000415809737 is a prime.
Together with 2000420004043, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2000420004043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000210002020 + 1000210002021.
It is an arithmetic number, because the mean of its divisors is an integer number (1000210002021).
Almost surely, 22000420004041 is an apocalyptic number.
It is an amenable number.
2000420004041 is a deficient number, since it is larger than the sum of its proper divisors (1).
2000420004041 is an equidigital number, since it uses as much as digits as its factorization.
2000420004041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 256, while the sum is 17.
Adding to 2000420004041 its reverse (1404000240002), we get a palindrome (3404420244043).
The spelling of 2000420004041 in words is "two trillion, four hundred twenty million, four thousand, forty-one".
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