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200043314 = 2100021657
BaseRepresentation
bin10111110110001…
…10101100110010
3111221102020211122
423323012230302
5402202341224
631503342242
74646224442
oct1373065462
9457366748
10200043314
11a2a12559
1256bb1982
13325a0c33
141c7d4122
151286715e
hexbec6b32

200043314 has 4 divisors (see below), whose sum is σ = 300064974. Its totient is φ = 100021656.

The previous prime is 200043313. The next prime is 200043329. The reversal of 200043314 is 413340002.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 193627225 + 6416089 = 13915^2 + 2533^2 .

It is a super-2 number, since 2×2000433142 = 80034654952205192, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 200043292 and 200043301.

It is not an unprimeable number, because it can be changed into a prime (200043313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50010827 + ... + 50010830.

Almost surely, 2200043314 is an apocalyptic number.

200043314 is a deficient number, since it is larger than the sum of its proper divisors (100021660).

200043314 is a wasteful number, since it uses less digits than its factorization.

200043314 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100021659.

The product of its (nonzero) digits is 288, while the sum is 17.

The square root of 200043314 is about 14143.6669219831. Note that the first 3 decimals coincide. The cubic root of 200043314 is about 584.8457615634.

Adding to 200043314 its reverse (413340002), we get a palindrome (613383316).

The spelling of 200043314 in words is "two hundred million, forty-three thousand, three hundred fourteen".

Divisors: 1 2 100021657 200043314