Base | Representation |
---|---|
bin | 1001000110001101000000… |
… | …10100110101110100010001 |
3 | 2121211101201201111012020210 |
4 | 10203012200110311310101 |
5 | 10110222403220442340 |
6 | 110313512255354333 |
7 | 4133160334546662 |
oct | 443064024656421 |
9 | 77741651435223 |
10 | 20004352515345 |
11 | 6412886534260 |
12 | 22b0b892229a9 |
13 | b2152cc5c4c3 |
14 | 4d2304335369 |
15 | 24a55c040180 |
hex | 1231a0535d11 |
20004352515345 has 64 divisors (see below), whose sum is σ = 35193941360640. Its totient is φ = 9622075276800.
The previous prime is 20004352515337. The next prime is 20004352515359. The reversal of 20004352515345 is 54351525340002.
It is not a de Polignac number, because 20004352515345 - 23 = 20004352515337 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 535989285 + ... + 536026605.
It is an arithmetic number, because the mean of its divisors is an integer number (549905333760).
Almost surely, 220004352515345 is an apocalyptic number.
It is an amenable number.
20004352515345 is a deficient number, since it is larger than the sum of its proper divisors (15189588845295).
20004352515345 is a wasteful number, since it uses less digits than its factorization.
20004352515345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 63046.
The product of its (nonzero) digits is 360000, while the sum is 39.
Adding to 20004352515345 its reverse (54351525340002), we get a palindrome (74355877855347).
The spelling of 20004352515345 in words is "twenty trillion, four billion, three hundred fifty-two million, five hundred fifteen thousand, three hundred forty-five".
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