Base | Representation |
---|---|
bin | 1001000110001110011010… |
… | …00001111111001001100011 |
3 | 2121211110122222210210000112 |
4 | 10203013031001333021203 |
5 | 10110230422223010210 |
6 | 110314114531241535 |
7 | 4133215042661546 |
oct | 443071501771143 |
9 | 77743588723015 |
10 | 20005102547555 |
11 | 6413130946594 |
12 | 22b11584492ab |
13 | b2161c468848 |
14 | 4d2375bb485d |
15 | 24a5a2ce6d05 |
hex | 1231cd07f263 |
20005102547555 has 32 divisors (see below), whose sum is σ = 25292113228800. Its totient is φ = 15160351485312.
The previous prime is 20005102547531. The next prime is 20005102547567. The reversal of 20005102547555 is 55574520150002.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20005102547555 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 25167512 + ... + 25950218.
It is an arithmetic number, because the mean of its divisors is an integer number (790378538400).
Almost surely, 220005102547555 is an apocalyptic number.
20005102547555 is a deficient number, since it is larger than the sum of its proper divisors (5287010681245).
20005102547555 is a wasteful number, since it uses less digits than its factorization.
20005102547555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 784883.
The product of its (nonzero) digits is 350000, while the sum is 41.
Adding to 20005102547555 its reverse (55574520150002), we get a palindrome (75579622697557).
The spelling of 20005102547555 in words is "twenty trillion, five billion, one hundred two million, five hundred forty-seven thousand, five hundred fifty-five".
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