200101102100113 has 2 divisors, whose sum is σ = 200101102100114. Its totient is φ = 200101102100112.

The previous prime is 200101102100063. The next prime is 200101102100171. The reversal of 200101102100113 is 311001201101002.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 198278728997904 + 1822373102209 = 14081148^2 + 1349953^2 .

It is a cyclic number.

It is not a de Polignac number, because 200101102100113 - 2⁴⁵ = 164916730011281 is a prime.

It is a super-3 number, since 3×200101102100113³ (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 200101102100093 and 200101102100102.

It is not a weakly prime, because it can be changed into another prime (200101102100173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100050551050056 + 100050551050057.

It is an arithmetic number, because the mean of its divisors is an integer number (100050551050057).

Almost surely, 2^{200101102100113} is an apocalyptic number.

It is an amenable number.

200101102100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

200101102100113 is an equidigital number, since it uses as much as digits as its factorization.

200101102100113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 200101102100113 its reverse (311001201101002), we get a palindrome (511102303201115).

The spelling of 200101102100113 in words is "two hundred trillion, one hundred one billion, one hundred two million, one hundred thousand, one hundred thirteen".