Base | Representation |
---|---|
bin | 10010101000101100… |
… | …100001010001100111 |
3 | 1220122112120000110002 |
4 | 102220230201101213 |
5 | 311440042041403 |
6 | 13105330051515 |
7 | 1305604101152 |
oct | 225054412147 |
9 | 56575500402 |
10 | 20010112103 |
11 | 8539206433 |
12 | 3a65419b9b |
13 | 1b6b808527 |
14 | d7b798c99 |
15 | 7c1ab7188 |
hex | 4a8b21467 |
20010112103 has 2 divisors, whose sum is σ = 20010112104. Its totient is φ = 20010112102.
The previous prime is 20010112093. The next prime is 20010112127. The reversal of 20010112103 is 30121101002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20010112103 - 214 = 20010095719 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20010112163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10005056051 + 10005056052.
It is an arithmetic number, because the mean of its divisors is an integer number (10005056052).
Almost surely, 220010112103 is an apocalyptic number.
20010112103 is a deficient number, since it is larger than the sum of its proper divisors (1).
20010112103 is an equidigital number, since it uses as much as digits as its factorization.
20010112103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 20010112103 its reverse (30121101002), we get a palindrome (50131213105).
The spelling of 20010112103 in words is "twenty billion, ten million, one hundred twelve thousand, one hundred three".
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