200101121113 has 2 divisors, whose sum is σ = 200101121114. Its totient is φ = 200101121112.

The previous prime is 200101121083. The next prime is 200101121147. The reversal of 200101121113 is 311121101002.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 166755439449 + 33345681664 = 408357^2 + 182608^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-200101121113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 200101121093 and 200101121102.

It is not a weakly prime, because it can be changed into another prime (200101121513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100050560556 + 100050560557.

It is an arithmetic number, because the mean of its divisors is an integer number (100050560557).

Almost surely, 2^200101121113 is an apocalyptic number.

It is an amenable number.

200101121113 is a deficient number, since it is larger than the sum of its proper divisors (1).

200101121113 is an equidigital number, since it uses as much as digits as its factorization.

200101121113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 200101121113 its reverse (311121101002), we get a palindrome (511222222115).

The spelling of 200101121113 in words is "two hundred billion, one hundred one million, one hundred twenty-one thousand, one hundred thirteen".