Base | Representation |
---|---|
bin | 1001000110010111110000… |
… | …00110110110101100101001 |
3 | 2121211221121200102111121022 |
4 | 10203023320012312230221 |
5 | 10110321211233224431 |
6 | 110320304453222225 |
7 | 4133453301264626 |
oct | 443137006665451 |
9 | 77757550374538 |
10 | 20010120211241 |
11 | 6415276218586 |
12 | 22b2118931975 |
13 | b21c3bb70304 |
14 | 4d26d035334d |
15 | 24a79858c07b |
hex | 1232f81b6b29 |
20010120211241 has 2 divisors, whose sum is σ = 20010120211242. Its totient is φ = 20010120211240.
The previous prime is 20010120211223. The next prime is 20010120211259. The reversal of 20010120211241 is 14211202101002.
It is a balanced prime because it is at equal distance from previous prime (20010120211223) and next prime (20010120211259).
It can be written as a sum of positive squares in only one way, i.e., 18321575897641 + 1688544313600 = 4280371^2 + 1299440^2 .
It is a cyclic number.
It is not a de Polignac number, because 20010120211241 - 218 = 20010119949097 is a prime.
It is not a weakly prime, because it can be changed into another prime (20010120271241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10005060105620 + 10005060105621.
It is an arithmetic number, because the mean of its divisors is an integer number (10005060105621).
Almost surely, 220010120211241 is an apocalyptic number.
It is an amenable number.
20010120211241 is a deficient number, since it is larger than the sum of its proper divisors (1).
20010120211241 is an equidigital number, since it uses as much as digits as its factorization.
20010120211241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 20010120211241 its reverse (14211202101002), we get a palindrome (34221322312243).
The spelling of 20010120211241 in words is "twenty trillion, ten billion, one hundred twenty million, two hundred eleven thousand, two hundred forty-one".
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