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2001012022013 is a prime number
BaseRepresentation
bin11101000111100101100…
…111000101101011111101
321002021221222010220011212
4131013211213011223331
5230241033034201023
64131130252054205
7264365641356404
oct35074547055375
97067858126155
102001012022013
11701696135a14
12283986a64365
13116905120574
146cbc704a63b
15370b6c85e78
hex1d1e59c5afd

2001012022013 has 2 divisors, whose sum is σ = 2001012022014. Its totient is φ = 2001012022012.

The previous prime is 2001012022007. The next prime is 2001012022021. The reversal of 2001012022013 is 3102202101002.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1746090031609 + 254921990404 = 1321397^2 + 504898^2 .

It is a cyclic number.

It is not a de Polignac number, because 2001012022013 - 216 = 2001011956477 is a prime.

It is a super-2 number, since 2×20010120220132 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2001012024013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000506011006 + 1000506011007.

It is an arithmetic number, because the mean of its divisors is an integer number (1000506011007).

Almost surely, 22001012022013 is an apocalyptic number.

It is an amenable number.

2001012022013 is a deficient number, since it is larger than the sum of its proper divisors (1).

2001012022013 is an equidigital number, since it uses as much as digits as its factorization.

2001012022013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 2001012022013 its reverse (3102202101002), we get a palindrome (5103214123015).

The spelling of 2001012022013 in words is "two trillion, one billion, twelve million, twenty-two thousand, thirteen".